51121431253 has 2 divisors, whose sum is σ = 51121431254. Its totient is φ = 51121431252.

The previous prime is 51121431241. The next prime is 51121431281. The reversal of 51121431253 is 35213412115.

It is an a-pointer prime, because the next prime (51121431281) can be obtained adding 51121431253 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51075096004 + 46335249 = 225998^2 + 6807^2 .

It is a cyclic number.

It is not a de Polignac number, because 51121431253 - 2²⁵ = 51087876821 is a prime.

It is a super-2 number, since 2×51121431253² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51121431203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25560715626 + 25560715627.

It is an arithmetic number, because the mean of its divisors is an integer number (25560715627).

Almost surely, 2^51121431253 is an apocalyptic number.

It is an amenable number.

51121431253 is a deficient number, since it is larger than the sum of its proper divisors (1).

51121431253 is an equidigital number, since it uses as much as digits as its factorization.

51121431253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3600, while the sum is 28.

Adding to 51121431253 its reverse (35213412115), we get a palindrome (86334843368).

The spelling of 51121431253 in words is "fifty-one billion, one hundred twenty-one million, four hundred thirty-one thousand, two hundred fifty-three".