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51034053433 = 1110093459671
BaseRepresentation
bin101111100001110111…
…011101101100111001
311212201122120112021011
4233201313131230321
51314004204202213
635240020513521
73454446203536
oct574167355471
9155648515234
1051034053433
111a709435770
129a8324b8a1
134a74070b6c
142681bc3d8d
1514da55103d
hexbe1dddb39

51034053433 has 8 divisors (see below), whose sum is σ = 55679150016. Its totient is φ = 46389896400.

The previous prime is 51034053407. The next prime is 51034053439. The reversal of 51034053433 is 33435043015.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51034053433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51034053395 and 51034053404.

It is not an unprimeable number, because it can be changed into a prime (51034053439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118813 + ... + 340858.

It is an arithmetic number, because the mean of its divisors is an integer number (6959893752).

Almost surely, 251034053433 is an apocalyptic number.

It is an amenable number.

51034053433 is a deficient number, since it is larger than the sum of its proper divisors (4645096583).

51034053433 is a wasteful number, since it uses less digits than its factorization.

51034053433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 469775.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 51034053433 its reverse (33435043015), we get a palindrome (84469096448).

The spelling of 51034053433 in words is "fifty-one billion, thirty-four million, fifty-three thousand, four hundred thirty-three".

Divisors: 1 11 10093 111023 459671 5056381 4639459403 51034053433