Base | Representation |
---|---|
bin | 100100011111011100110… |
… | …1011011111101100110111 |
3 | 122202110110210211120022011 |
4 | 1020332321223133230313 |
5 | 1124132410024141211 |
6 | 14400003305145051 |
7 | 1025226564535450 |
oct | 110767153375467 |
9 | 18673423746264 |
10 | 5015342021431 |
11 | 1663aa3904315 |
12 | 69000ba8b187 |
13 | 2a4c38731a61 |
14 | 134a5b19c127 |
15 | 8a6d9595921 |
hex | 48fb9adfb37 |
5015342021431 has 16 divisors (see below), whose sum is σ = 6196561576960. Its totient is φ = 3962538053280.
The previous prime is 5015342021429. The next prime is 5015342021449. The reversal of 5015342021431 is 1341202435105.
It is a cyclic number.
It is not a de Polignac number, because 5015342021431 - 21 = 5015342021429 is a prime.
It is a super-2 number, since 2×50153420214312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5015342021393 and 5015342021402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5015342021231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 509580735 + ... + 509590576.
It is an arithmetic number, because the mean of its divisors is an integer number (387285098560).
Almost surely, 25015342021431 is an apocalyptic number.
5015342021431 is a deficient number, since it is larger than the sum of its proper divisors (1181219555529).
5015342021431 is a wasteful number, since it uses less digits than its factorization.
5015342021431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1019171374.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 5015342021431 its reverse (1341202435105), we get a palindrome (6356544456536).
The spelling of 5015342021431 in words is "five trillion, fifteen billion, three hundred forty-two million, twenty-one thousand, four hundred thirty-one".
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