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4978481953 is a prime number
BaseRepresentation
bin1001010001011110…
…11001101100100001
3110211221220002100111
410220233121230201
540143442410303
62142002051321
7234241253434
oct45057315441
913757802314
104978481953
1121252501a5
12b6b349b41
13614566513
1435329d81b
151e2105b6d
hex128bd9b21

4978481953 has 2 divisors, whose sum is σ = 4978481954. Its totient is φ = 4978481952.

The previous prime is 4978481927. The next prime is 4978482077. The reversal of 4978481953 is 3591848794.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4538447424 + 440034529 = 67368^2 + 20977^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4978481953 is a prime.

It is a super-3 number, since 3×49784819533 (a number of 30 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4978481653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2489240976 + 2489240977.

It is an arithmetic number, because the mean of its divisors is an integer number (2489240977).

Almost surely, 24978481953 is an apocalyptic number.

It is an amenable number.

4978481953 is a deficient number, since it is larger than the sum of its proper divisors (1).

4978481953 is an equidigital number, since it uses as much as digits as its factorization.

4978481953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8709120, while the sum is 58.

The square root of 4978481953 is about 70558.3584913935. The cubic root of 4978481953 is about 1707.5193964357.

The spelling of 4978481953 in words is "four billion, nine hundred seventy-eight million, four hundred eighty-one thousand, nine hundred fifty-three".