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44330012114317 is a prime number
BaseRepresentation
bin10100001010001011000101…
…00111111111110110001101
312210221220111202122010002021
422011011202213333312031
521302300331100124232
6234140532035130141
712223511011534666
oct1205054247776615
9183856452563067
1044330012114317
11131412861806a6
124b7b553443951
131b973c0c38c07
14ad382683a36d
1551d1d30a4397
hex2851629ffd8d

44330012114317 has 2 divisors, whose sum is σ = 44330012114318. Its totient is φ = 44330012114316.

The previous prime is 44330012114291. The next prime is 44330012114359. The reversal of 44330012114317 is 71341121003344.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42639476471881 + 1690535642436 = 6529891^2 + 1300206^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44330012114317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44330012114617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22165006057158 + 22165006057159.

It is an arithmetic number, because the mean of its divisors is an integer number (22165006057159).

Almost surely, 244330012114317 is an apocalyptic number.

It is an amenable number.

44330012114317 is a deficient number, since it is larger than the sum of its proper divisors (1).

44330012114317 is an equidigital number, since it uses as much as digits as its factorization.

44330012114317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 34.

The spelling of 44330012114317 in words is "forty-four trillion, three hundred thirty billion, twelve million, one hundred fourteen thousand, three hundred seventeen".