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43401034134 = 2322411168563
BaseRepresentation
bin101000011010111001…
…110011100110010110
311011000200200222020200
4220122321303212112
51202341131043014
631534350441330
73064342463133
oct503271634626
9134020628220
1043401034134
1117451830357
1284b2b03246
13412887acb3
14215a16758a
1511e0395a09
hexa1ae73996

43401034134 has 12 divisors (see below), whose sum is σ = 94035573996. Its totient is φ = 14467011372.

The previous prime is 43401034121. The next prime is 43401034147. The reversal of 43401034134 is 43143010434.

It is an interprime number because it is at equal distance from previous prime (43401034121) and next prime (43401034147).

It is a junction number, because it is equal to n+sod(n) for n = 43401034098 and 43401034107.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1205584264 + ... + 1205584299.

It is an arithmetic number, because the mean of its divisors is an integer number (7836297833).

Almost surely, 243401034134 is an apocalyptic number.

43401034134 is an abundant number, since it is smaller than the sum of its proper divisors (50634539862).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

43401034134 is a wasteful number, since it uses less digits than its factorization.

43401034134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2411168571 (or 2411168568 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 43401034134 its reverse (43143010434), we get a palindrome (86544044568).

The spelling of 43401034134 in words is "forty-three billion, four hundred one million, thirty-four thousand, one hundred thirty-four".

Divisors: 1 2 3 6 9 18 2411168563 4822337126 7233505689 14467011378 21700517067 43401034134