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43401034013 is a prime number
BaseRepresentation
bin101000011010111001…
…110011100100011101
311011000200200222002012
4220122321303210131
51202341131042023
631534350441005
73064342462601
oct503271634435
9134020628065
1043401034013
1117451830257
1284b2b03165
13412887ac1c
14215a167501
1511e0395978
hexa1ae7391d

43401034013 has 2 divisors, whose sum is σ = 43401034014. Its totient is φ = 43401034012.

The previous prime is 43401033967. The next prime is 43401034037. The reversal of 43401034013 is 31043010434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24479105764 + 18921928249 = 156458^2 + 137557^2 .

It is a cyclic number.

It is not a de Polignac number, because 43401034013 - 216 = 43400968477 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 43401034013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43401034213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21700517006 + 21700517007.

It is an arithmetic number, because the mean of its divisors is an integer number (21700517007).

Almost surely, 243401034013 is an apocalyptic number.

It is an amenable number.

43401034013 is a deficient number, since it is larger than the sum of its proper divisors (1).

43401034013 is an equidigital number, since it uses as much as digits as its factorization.

43401034013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 43401034013 its reverse (31043010434), we get a palindrome (74444044447).

The spelling of 43401034013 in words is "forty-three billion, four hundred one million, thirty-four thousand, thirteen".