Base | Representation |
---|---|
bin | 101000010111111111… |
… | …010011010010100011 |
3 | 11010220021201001020100 |
4 | 220113333103102203 |
5 | 1202241122034021 |
6 | 31525442513443 |
7 | 3063210064332 |
oct | 502777232243 |
9 | 133807631210 |
10 | 43352143011 |
11 | 17427177771 |
12 | 849a665883 |
13 | 411b6c0538 |
14 | 215387bd19 |
15 | 11dae39626 |
hex | a17fd34a3 |
43352143011 has 12 divisors (see below), whose sum is σ = 62623030392. Its totient is φ = 28899920256.
The previous prime is 43352142991. The next prime is 43352143013. The reversal of 43352143011 is 11034125334.
It is a happy number.
43352143011 is a `hidden beast` number, since 4 + 3 + 352 + 1 + 4 + 301 + 1 = 666.
It is not a de Polignac number, because 43352143011 - 26 = 43352142947 is a prime.
It is a super-2 number, since 2×433521430112 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (43352143013) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 72820 + ... + 303326.
It is an arithmetic number, because the mean of its divisors is an integer number (5218585866).
Almost surely, 243352143011 is an apocalyptic number.
43352143011 is a deficient number, since it is larger than the sum of its proper divisors (19270887381).
43352143011 is a wasteful number, since it uses less digits than its factorization.
43352143011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 251410 (or 251407 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 43352143011 its reverse (11034125334), we get a palindrome (54386268345).
The spelling of 43352143011 in words is "forty-three billion, three hundred fifty-two million, one hundred forty-three thousand, eleven".
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