43312240120 has 16 divisors (see below), whose sum is σ = 97452540360. Its totient is φ = 17324896032.

The previous prime is 43312240099. The next prime is 43312240151. The reversal of 43312240120 is 2104221334.

43312240120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×43312240120² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43312240091 and 43312240100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541402962 + ... + 541403041.

Almost surely, 2^43312240120 is an apocalyptic number.

43312240120 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

43312240120 is an abundant number, since it is smaller than the sum of its proper divisors (54140300240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

43312240120 is a wasteful number, since it uses less digits than its factorization.

43312240120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1082806014 (or 1082806010 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 43312240120 its reverse (2104221334), we get a palindrome (45416461454).

The spelling of 43312240120 in words is "forty-three billion, three hundred twelve million, two hundred forty thousand, one hundred twenty".