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430121113 = 1912251943
BaseRepresentation
bin11001101000110…
…010000010011001
31002222100102020121
4121220302002121
51340102333423
6110402553241
713441653262
oct3150620231
91088312217
10430121113
112008793a4
12100068821
136b159746
14411a5969
1527b6345d
hex19a32099

430121113 has 4 divisors (see below), whose sum is σ = 432373248. Its totient is φ = 427868980.

The previous prime is 430121101. The next prime is 430121117. The reversal of 430121113 is 311121034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-430121113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (430121117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125781 + ... + 1126162.

It is an arithmetic number, because the mean of its divisors is an integer number (108093312).

Almost surely, 2430121113 is an apocalyptic number.

It is an amenable number.

430121113 is a deficient number, since it is larger than the sum of its proper divisors (2252135).

430121113 is a wasteful number, since it uses less digits than its factorization.

430121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2252134.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 430121113 is about 20739.3614414716. The cubic root of 430121113 is about 754.8550884841.

Adding to 430121113 its reverse (311121034), we get a palindrome (741242147).

The spelling of 430121113 in words is "four hundred thirty million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 191 2251943 430121113