Search a number
-
+
42032401314131 is a prime number
BaseRepresentation
bin10011000111010011011100…
…10110010111000101010011
312111211020222022120011101002
421203221232112113011103
521002124324214023011
6225221230225532215
711565512042136344
oct1143515626270523
9174736868504332
1042032401314131
1112435928839818
12486a1b21a406b
131a5b83b84ca57
14a545442960cb
154cd55c558c3b
hex263a6e597153

42032401314131 has 2 divisors, whose sum is σ = 42032401314132. Its totient is φ = 42032401314130.

The previous prime is 42032401314121. The next prime is 42032401314139. The reversal of 42032401314131 is 13141310423024.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 42032401314131 - 234 = 42015221444947 is a prime.

It is a super-2 number, since 2×420324013141312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42032401314094 and 42032401314103.

It is not a weakly prime, because it can be changed into another prime (42032401314139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21016200657065 + 21016200657066.

It is an arithmetic number, because the mean of its divisors is an integer number (21016200657066).

Almost surely, 242032401314131 is an apocalyptic number.

42032401314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

42032401314131 is an equidigital number, since it uses as much as digits as its factorization.

42032401314131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 42032401314131 its reverse (13141310423024), we get a palindrome (55173711737155).

The spelling of 42032401314131 in words is "forty-two trillion, thirty-two billion, four hundred one million, three hundred fourteen thousand, one hundred thirty-one".