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4145141224351 is a prime number
BaseRepresentation
bin111100010100011101101…
…010111001001110011111
3112200021100000111211122001
4330110131222321032133
51020403222123134401
612452130202103131
7605322315026521
oct74243552711637
915607300454561
104145141224351
111358a43180756
1256b4334aaaa7
13240b678649ca
141048a96b1a11
1572c5822c601
hex3c51dab939f

4145141224351 has 2 divisors, whose sum is σ = 4145141224352. Its totient is φ = 4145141224350.

The previous prime is 4145141224327. The next prime is 4145141224363. The reversal of 4145141224351 is 1534221415414.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4145141224351 - 213 = 4145141216159 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4145141224351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4145151224351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072570612175 + 2072570612176.

It is an arithmetic number, because the mean of its divisors is an integer number (2072570612176).

Almost surely, 24145141224351 is an apocalyptic number.

4145141224351 is a deficient number, since it is larger than the sum of its proper divisors (1).

4145141224351 is an equidigital number, since it uses as much as digits as its factorization.

4145141224351 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 76800, while the sum is 37.

Adding to 4145141224351 its reverse (1534221415414), we get a palindrome (5679362639765).

The spelling of 4145141224351 in words is "four trillion, one hundred forty-five billion, one hundred forty-one million, two hundred twenty-four thousand, three hundred fifty-one".