Base | Representation |
---|---|
bin | 101111000100100111101101… |
… | …0101011010011001010011111 |
3 | 2000022000221001001021102202011 |
4 | 1132021033122223103022133 |
5 | 413232304232130120223 |
6 | 4024340330540212051 |
7 | 153133140463630312 |
oct | 13611173253231237 |
9 | 2008027031242664 |
10 | 414051401020063 |
11 | 10aa2523863a454 |
12 | 3a531b2853a027 |
13 | 14a05b58589571 |
14 | 74362a2502979 |
15 | 32d06618b880d |
hex | 17893daad329f |
414051401020063 has 2 divisors, whose sum is σ = 414051401020064. Its totient is φ = 414051401020062.
The previous prime is 414051401020027. The next prime is 414051401020073. The reversal of 414051401020063 is 360020104150414.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 414051401020063 - 221 = 414051398922911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (414051401020073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207025700510031 + 207025700510032.
It is an arithmetic number, because the mean of its divisors is an integer number (207025700510032).
Almost surely, 2414051401020063 is an apocalyptic number.
414051401020063 is a deficient number, since it is larger than the sum of its proper divisors (1).
414051401020063 is an equidigital number, since it uses as much as digits as its factorization.
414051401020063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 414051401020063 its reverse (360020104150414), we get a palindrome (774071505170477).
The spelling of 414051401020063 in words is "four hundred fourteen trillion, fifty-one billion, four hundred one million, twenty thousand, sixty-three".
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