412414831 has 2 divisors, whose sum is σ = 412414832. Its totient is φ = 412414830.

The previous prime is 412414813. The next prime is 412414843. The reversal of 412414831 is 138414214.

Together with previous prime (412414813) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 412414831 - 2²³ = 404026223 is a prime.

It is a super-2 number, since 2×412414831² = 340171985657517122, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 412414831.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412414861) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206207415 + 206207416.

It is an arithmetic number, because the mean of its divisors is an integer number (206207416).

Almost surely, 2^412414831 is an apocalyptic number.

412414831 is a deficient number, since it is larger than the sum of its proper divisors (1).

412414831 is an equidigital number, since it uses as much as digits as its factorization.

412414831 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3072, while the sum is 28.

The square root of 412414831 is about 20307.9991875123. Note that the first 3 decimals coincide. The cubic root of 412414831 is about 744.3515405949.

The spelling of 412414831 in words is "four hundred twelve million, four hundred fourteen thousand, eight hundred thirty-one".