Base | Representation |
---|---|
bin | 1011111111111111011… |
… | …01111101101000110111 |
3 | 1110102020202000111011022 |
4 | 11333333231331220313 |
5 | 23223403401212101 |
6 | 513225155531355 |
7 | 41534323204013 |
oct | 5777755755067 |
9 | 1412222014138 |
10 | 412312132151 |
11 | 1499514a4527 |
12 | 67aaa5b9b5b |
13 | 2cb5b35ab3a |
14 | 15d55431543 |
15 | aad2772a1b |
hex | 5fffb7da37 |
412312132151 has 2 divisors, whose sum is σ = 412312132152. Its totient is φ = 412312132150.
The previous prime is 412312132139. The next prime is 412312132153. The reversal of 412312132151 is 151231213214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412312132151 - 226 = 412245023287 is a prime.
Together with 412312132153, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 412312132151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (412312132153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206156066075 + 206156066076.
It is an arithmetic number, because the mean of its divisors is an integer number (206156066076).
Almost surely, 2412312132151 is an apocalyptic number.
412312132151 is a deficient number, since it is larger than the sum of its proper divisors (1).
412312132151 is an equidigital number, since it uses as much as digits as its factorization.
412312132151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 26.
Adding to 412312132151 its reverse (151231213214), we get a palindrome (563543345365).
The spelling of 412312132151 in words is "four hundred twelve billion, three hundred twelve million, one hundred thirty-two thousand, one hundred fifty-one".
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