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404441210113 is a prime number
BaseRepresentation
bin1011110001010101001…
…00110001110100000001
31102122221012111012221021
411320222210301310001
523111243422210423
6505444150425441
741135300364313
oct5705244616401
91378835435837
10404441210113
11146582579286
1266472662281
132c1a579c915
1415809d677b3
15a7c177295d
hex5e2a931d01

404441210113 has 2 divisors, whose sum is σ = 404441210114. Its totient is φ = 404441210112.

The previous prime is 404441210083. The next prime is 404441210141. The reversal of 404441210113 is 311012144404.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 360951027264 + 43490182849 = 600792^2 + 208543^2 .

It is a cyclic number.

It is not a de Polignac number, because 404441210113 - 25 = 404441210081 is a prime.

It is not a weakly prime, because it can be changed into another prime (404441210213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202220605056 + 202220605057.

It is an arithmetic number, because the mean of its divisors is an integer number (202220605057).

Almost surely, 2404441210113 is an apocalyptic number.

It is an amenable number.

404441210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

404441210113 is an equidigital number, since it uses as much as digits as its factorization.

404441210113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 404441210113 its reverse (311012144404), we get a palindrome (715453354517).

The spelling of 404441210113 in words is "four hundred four billion, four hundred forty-one million, two hundred ten thousand, one hundred thirteen".