Base | Representation |
---|---|
bin | 111010110100101000111… |
… | …100011000111100111101 |
3 | 112022102202102200020212011 |
4 | 322310220330120330331 |
5 | 1012212012243120041 |
6 | 12332552354411221 |
7 | 565020515546665 |
oct | 72645074307475 |
9 | 15272672606764 |
10 | 4042251145021 |
11 | 1319344432241 |
12 | 5534b9890b11 |
13 | 23424b378c6b |
14 | dd90889d1a5 |
15 | 70235412e81 |
hex | 3ad28f18f3d |
4042251145021 has 2 divisors, whose sum is σ = 4042251145022. Its totient is φ = 4042251145020.
The previous prime is 4042251144889. The next prime is 4042251145033. The reversal of 4042251145021 is 1205411522404.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3092287080100 + 949964064921 = 1758490^2 + 974661^2 .
It is a cyclic number.
It is not a de Polignac number, because 4042251145021 - 215 = 4042251112253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4042251145321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021125572510 + 2021125572511.
It is an arithmetic number, because the mean of its divisors is an integer number (2021125572511).
Almost surely, 24042251145021 is an apocalyptic number.
It is an amenable number.
4042251145021 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042251145021 is an equidigital number, since it uses as much as digits as its factorization.
4042251145021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 4042251145021 its reverse (1205411522404), we get a palindrome (5247662667425).
The spelling of 4042251145021 in words is "four trillion, forty-two billion, two hundred fifty-one million, one hundred forty-five thousand, twenty-one".
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