Base | Representation |
---|---|
bin | 10010010011010010101111… |
… | …01010110100010001111111 |
3 | 12021111102012011021000010211 |
4 | 21021221113222310101333 |
5 | 20233334400441434003 |
6 | 221332235303213251 |
7 | 11322425260064104 |
oct | 1111512752642177 |
9 | 167442164230124 |
10 | 40245314405503 |
11 | 11906a3a874879 |
12 | 461b98a447227 |
13 | 195c16999a71c |
14 | 9d1c528acaab |
15 | 49bd164d696d |
hex | 249a57ab447f |
40245314405503 has 2 divisors, whose sum is σ = 40245314405504. Its totient is φ = 40245314405502.
The previous prime is 40245314405497. The next prime is 40245314405507. The reversal of 40245314405503 is 30550441354204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40245314405503 - 29 = 40245314404991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40245314405507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20122657202751 + 20122657202752.
It is an arithmetic number, because the mean of its divisors is an integer number (20122657202752).
Almost surely, 240245314405503 is an apocalyptic number.
40245314405503 is a deficient number, since it is larger than the sum of its proper divisors (1).
40245314405503 is an equidigital number, since it uses as much as digits as its factorization.
40245314405503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 40245314405503 its reverse (30550441354204), we get a palindrome (70795755759707).
The spelling of 40245314405503 in words is "forty trillion, two hundred forty-five billion, three hundred fourteen million, four hundred five thousand, five hundred three".
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