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4024113 = 31341371
BaseRepresentation
bin1111010110011100110001
321120110001020
433112130301
52012232423
6222130053
746130052
oct17263461
97513036
104024113
1122a9415
121420929
13aab842
1476a729
155474e3
hex3d6731

4024113 has 4 divisors (see below), whose sum is σ = 5365488. Its totient is φ = 2682740.

The previous prime is 4024091. The next prime is 4024123. The reversal of 4024113 is 3114204.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4024113 - 26 = 4024049 is a prime.

It is a D-number.

It is a junction number, because it is equal to n+sod(n) for n = 4024092 and 4024101.

It is not an unprimeable number, because it can be changed into a prime (4024123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670683 + ... + 670688.

It is an arithmetic number, because the mean of its divisors is an integer number (1341372).

Almost surely, 24024113 is an apocalyptic number.

It is an amenable number.

4024113 is a deficient number, since it is larger than the sum of its proper divisors (1341375).

4024113 is a wasteful number, since it uses less digits than its factorization.

4024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1341374.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 4024113 is about 2006.0191923309. The cubic root of 4024113 is about 159.0584413941.

Adding to 4024113 its reverse (3114204), we get a palindrome (7138317).

Subtracting from 4024113 its reverse (3114204), we obtain a palindrome (909909).

The spelling of 4024113 in words is "four million, twenty-four thousand, one hundred thirteen".

Divisors: 1 3 1341371 4024113