40141406430113 has 4 divisors (see below), whose sum is σ = 40141465269168. Its totient is φ = 40141347591060.

The previous prime is 40141406430101. The next prime is 40141406430193. The reversal of 40141406430113 is 31103460414104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40141406430113 - 2¹⁴ = 40141406413729 is a prime.

It is a super-2 number, since 2×40141406430113² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 40141406430113.

It is not an unprimeable number, because it can be changed into a prime (40141406430193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28384043 + ... + 29764688.

It is an arithmetic number, because the mean of its divisors is an integer number (10035366317292).

Almost surely, 2^{40141406430113} is an apocalyptic number.

It is an amenable number.

40141406430113 is a deficient number, since it is larger than the sum of its proper divisors (58839055).

40141406430113 is an equidigital number, since it uses as much as digits as its factorization.

40141406430113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58839054.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 40141406430113 its reverse (31103460414104), we get a palindrome (71244866844217).

The spelling of 40141406430113 in words is "forty trillion, one hundred forty-one billion, four hundred six million, four hundred thirty thousand, one hundred thirteen".