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40141406427763 is a prime number
BaseRepresentation
bin10010010000010001001100…
…10001010101101001110011
312021010110222122001211020211
421020020212101111221303
520230134100021142023
6221212412454444551
711312056320616354
oct1110104621255163
9167113878054224
1040141406427763
1111876969498203
12460380b963757
13195241a648b24
149cabd680dd2b
15499284152a0d
hex248226455a73

40141406427763 has 2 divisors, whose sum is σ = 40141406427764. Its totient is φ = 40141406427762.

The previous prime is 40141406427743. The next prime is 40141406427781. The reversal of 40141406427763 is 36772460414104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40141406427763 - 213 = 40141406419571 is a prime.

It is a super-2 number, since 2×401414064277632 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40141406427743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20070703213881 + 20070703213882.

It is an arithmetic number, because the mean of its divisors is an integer number (20070703213882).

Almost surely, 240141406427763 is an apocalyptic number.

40141406427763 is a deficient number, since it is larger than the sum of its proper divisors (1).

40141406427763 is an equidigital number, since it uses as much as digits as its factorization.

40141406427763 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2709504, while the sum is 49.

The spelling of 40141406427763 in words is "forty trillion, one hundred forty-one billion, four hundred six million, four hundred twenty-seven thousand, seven hundred sixty-three".