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40133153 is a prime number
BaseRepresentation
bin1001100100011…
…0001000100001
32210111222100002
42121012020201
540233230103
63552105345
7665061164
oct231061041
983458302
1040133153
11207216a5
1211535255
138412338
145489adb
1537cb488
hex2646221

40133153 has 2 divisors, whose sum is σ = 40133154. Its totient is φ = 40133152.

The previous prime is 40133131. The next prime is 40133167. The reversal of 40133153 is 35133104.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28654609 + 11478544 = 5353^2 + 3388^2 .

It is a cyclic number.

It is not a de Polignac number, because 40133153 - 216 = 40067617 is a prime.

It is a super-2 number, since 2×401331532 = 3221339939442818, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (40135153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066576 + 20066577.

It is an arithmetic number, because the mean of its divisors is an integer number (20066577).

Almost surely, 240133153 is an apocalyptic number.

It is an amenable number.

40133153 is a deficient number, since it is larger than the sum of its proper divisors (1).

40133153 is an equidigital number, since it uses as much as digits as its factorization.

40133153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 20.

The square root of 40133153 is about 6335.0732434598. The cubic root of 40133153 is about 342.3742497494.

Adding to 40133153 its reverse (35133104), we get a palindrome (75266257).

The spelling of 40133153 in words is "forty million, one hundred thirty-three thousand, one hundred fifty-three".