40131133102113 has 4 divisors (see below), whose sum is σ = 53508177469488. Its totient is φ = 26754088734740.

The previous prime is 40131133102003. The next prime is 40131133102129. The reversal of 40131133102113 is 31120133113104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40131133102113 - 2¹⁰ = 40131133101089 is a prime.

It is a super-2 number, since 2×40131133102113² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (40131133102213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6688522183683 + ... + 6688522183688.

It is an arithmetic number, because the mean of its divisors is an integer number (13377044367372).

Almost surely, 2^{40131133102113} is an apocalyptic number.

It is an amenable number.

40131133102113 is a deficient number, since it is larger than the sum of its proper divisors (13377044367375).

40131133102113 is a wasteful number, since it uses less digits than its factorization.

40131133102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13377044367374.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 40131133102113 its reverse (31120133113104), we get a palindrome (71251266215217).

The spelling of 40131133102113 in words is "forty trillion, one hundred thirty-one billion, one hundred thirty-three million, one hundred two thousand, one hundred thirteen".