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394332601007 = 2525891561163
BaseRepresentation
bin1011011110100000000…
…11011111101010101111
31101200211201100200010102
411233100003133222233
522430043121213012
6501053124101315
740326633542612
oct5572003375257
91350751320112
10394332601007
11142265522684
126451123483b
132b254446207
141512b612179
15a3ce0ae2c2
hex5bd00dfaaf

394332601007 has 4 divisors (see below), whose sum is σ = 394334414760. Its totient is φ = 394330787256.

The previous prime is 394332600983. The next prime is 394332601057. The reversal of 394332601007 is 700106233493.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 394332601007 - 236 = 325613124271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (394332601057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 527993 + ... + 1033170.

It is an arithmetic number, because the mean of its divisors is an integer number (98583603690).

Almost surely, 2394332601007 is an apocalyptic number.

394332601007 is a deficient number, since it is larger than the sum of its proper divisors (1813753).

394332601007 is a wasteful number, since it uses less digits than its factorization.

394332601007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1813752.

The product of its (nonzero) digits is 81648, while the sum is 38.

The spelling of 394332601007 in words is "three hundred ninety-four billion, three hundred thirty-two million, six hundred one thousand, seven".

Divisors: 1 252589 1561163 394332601007