351264413231 has 4 divisors (see below), whose sum is σ = 371927025792. Its totient is φ = 330601800672.

The previous prime is 351264413209. The next prime is 351264413251. The reversal of 351264413231 is 132314462153.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 132314462153 = 211493 ⋅625621.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-351264413231 is a prime.

It is a super-4 number, since 4×351264413231⁴ (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 351264413191 and 351264413200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (351264413251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10331306255 + ... + 10331306288.

It is an arithmetic number, because the mean of its divisors is an integer number (92981756448).

Almost surely, 2^351264413231 is an apocalyptic number.

351264413231 is a deficient number, since it is larger than the sum of its proper divisors (20662612561).

351264413231 is a wasteful number, since it uses less digits than its factorization.

351264413231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20662612560.

The product of its digits is 51840, while the sum is 35.

Adding to 351264413231 its reverse (132314462153), we get a palindrome (483578875384).

The spelling of 351264413231 in words is "three hundred fifty-one billion, two hundred sixty-four million, four hundred thirteen thousand, two hundred thirty-one".