35114113 has 4 divisors (see below), whose sum is σ = 35127108. Its totient is φ = 35101120.

The previous prime is 35114111. The next prime is 35114117. The reversal of 35114113 is 31141153.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 9591409 + 25522704 = 3097^2 + 5052^2 .

It is a cyclic number.

It is not a de Polignac number, because 35114113 - 2¹ = 35114111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35114111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 748 + ... + 8413.

It is an arithmetic number, because the mean of its divisors is an integer number (8781777).

Almost surely, 2^35114113 is an apocalyptic number.

It is an amenable number.

35114113 is a deficient number, since it is larger than the sum of its proper divisors (12995).

35114113 is an equidigital number, since it uses as much as digits as its factorization.

35114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12994.

The product of its digits is 180, while the sum is 19.

The square root of 35114113 is about 5925.7162436283. The cubic root of 35114113 is about 327.4617417384.

Adding to 35114113 its reverse (31141153), we get a palindrome (66255266).

The spelling of 35114113 in words is "thirty-five million, one hundred fourteen thousand, one hundred thirteen".