Base | Representation |
---|---|
bin | 110001110100000001100… |
… | …000110011001100001110 |
3 | 110010020122201111021102211 |
4 | 301310001200303030032 |
5 | 422041014230413124 |
6 | 11140320151341034 |
7 | 502211651361151 |
oct | 61640140631416 |
9 | 13106581437384 |
10 | 3423114310414 |
11 | 10aa809873657 |
12 | 47350a08177a |
13 | 1baa4bb116a6 |
14 | bb972c21c98 |
15 | 5e09a4cbe94 |
hex | 31d0183330e |
3423114310414 has 8 divisors (see below), whose sum is σ = 5142534670440. Its totient is φ = 1708936086936.
The previous prime is 3423114310409. The next prime is 3423114310477. The reversal of 3423114310414 is 4140134113243.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×34231143104143 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310532504 + ... + 1310535115.
It is an arithmetic number, because the mean of its divisors is an integer number (642816833805).
Almost surely, 23423114310414 is an apocalyptic number.
3423114310414 is a deficient number, since it is larger than the sum of its proper divisors (1719420360026).
3423114310414 is a wasteful number, since it uses less digits than its factorization.
3423114310414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2621068274.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 3423114310414 its reverse (4140134113243), we get a palindrome (7563248423657).
The spelling of 3423114310414 in words is "three trillion, four hundred twenty-three billion, one hundred fourteen million, three hundred ten thousand, four hundred fourteen".
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