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342113433 = 3373082103
BaseRepresentation
bin10100011001000…
…011110010011001
3212211202011101220
4110121003302121
51200040112213
653540402253
711322626154
oct2431036231
9784664356
10342113433
11166128982
12966a6389
1355b545ac
1433616c9b
152007be23
hex14643c99

342113433 has 8 divisors (see below), whose sum is σ = 468479808. Its totient is φ = 221911344.

The previous prime is 342113417. The next prime is 342113483. The reversal of 342113433 is 334311243.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 342113433 - 24 = 342113417 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (342113483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1540941 + ... + 1541162.

It is an arithmetic number, because the mean of its divisors is an integer number (58559976).

Almost surely, 2342113433 is an apocalyptic number.

It is an amenable number.

342113433 is a deficient number, since it is larger than the sum of its proper divisors (126366375).

342113433 is a wasteful number, since it uses less digits than its factorization.

342113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3082143.

The product of its digits is 2592, while the sum is 24.

The square root of 342113433 is about 18496.3086317243. The cubic root of 342113433 is about 699.3963728244.

Adding to 342113433 its reverse (334311243), we get a palindrome (676424676).

The spelling of 342113433 in words is "three hundred forty-two million, one hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 3 37 111 3082103 9246309 114037811 342113433