Base | Representation |
---|---|
bin | 110001100010101000100… |
… | …101101001110111011101 |
3 | 110001110110110021010202020 |
4 | 301202220211221313131 |
5 | 421234244242312113 |
6 | 11123551310450353 |
7 | 500651155065165 |
oct | 61425045516735 |
9 | 13043413233666 |
10 | 3404442541533 |
11 | 10a28a8074300 |
12 | 46b978b039b9 |
13 | 1b9064677837 |
14 | baac10c95a5 |
15 | 5d85617b023 |
hex | 318a8969ddd |
3404442541533 has 24 divisors (see below), whose sum is σ = 5040868426944. Its totient is φ = 2042027370240.
The previous prime is 3404442541519. The next prime is 3404442541579. The reversal of 3404442541533 is 3351452444043.
It is not a de Polignac number, because 3404442541533 - 24 = 3404442541517 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3404442541333) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 48308241 + ... + 48378662.
It is an arithmetic number, because the mean of its divisors is an integer number (210036184456).
Almost surely, 23404442541533 is an apocalyptic number.
3404442541533 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
3404442541533 is a deficient number, since it is larger than the sum of its proper divisors (1636425885411).
3404442541533 is a wasteful number, since it uses less digits than its factorization.
3404442541533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96687025 (or 96687014 counting only the distinct ones).
The product of its (nonzero) digits is 1382400, while the sum is 42.
Adding to 3404442541533 its reverse (3351452444043), we get a palindrome (6755894985576).
The spelling of 3404442541533 in words is "three trillion, four hundred four billion, four hundred forty-two million, five hundred forty-one thousand, five hundred thirty-three".
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