Base | Representation |
---|---|
bin | 1001101110001110010… |
… | …10111101100110010001 |
3 | 1011221020210120120011110 |
4 | 10313013022331212101 |
5 | 20433120312142041 |
6 | 413243505003533 |
7 | 33064112222043 |
oct | 4670712754621 |
9 | 1157223516143 |
10 | 334054021521 |
11 | 119742871740 |
12 | 548aa0235a9 |
13 | 2566907b0bc |
14 | 1224db63a93 |
15 | 8a5217e516 |
hex | 4dc72bd991 |
334054021521 has 16 divisors (see below), whose sum is σ = 488363249088. Its totient is φ = 201429278400.
The previous prime is 334054021471. The next prime is 334054021547. The reversal of 334054021521 is 125120450433.
It is not a de Polignac number, because 334054021521 - 27 = 334054021393 is a prime.
It is a super-3 number, since 3×3340540215213 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (334054021321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25686010 + ... + 25699011.
It is an arithmetic number, because the mean of its divisors is an integer number (30522703068).
Almost surely, 2334054021521 is an apocalyptic number.
It is an amenable number.
334054021521 is a deficient number, since it is larger than the sum of its proper divisors (154309227567).
334054021521 is a wasteful number, since it uses less digits than its factorization.
334054021521 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51385232.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 334054021521 its reverse (125120450433), we get a palindrome (459174471954).
The spelling of 334054021521 in words is "three hundred thirty-four billion, fifty-four million, twenty-one thousand, five hundred twenty-one".
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