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33215430055 = 57359790263
BaseRepresentation
bin11110111011110010…
…110011110110100111
310011201211200200012011
4132323302303312213
51021011122230210
623131533535051
72254052332333
oct367362636647
9104654620164
1033215430055
11130a5276245
12652b944487
1331945a6c32
1418714cc7c3
15ce6073d8a
hex7bbcb3da7

33215430055 has 8 divisors (see below), whose sum is σ = 39859499232. Its totient is φ = 26571688608.

The previous prime is 33215430047. The next prime is 33215430071. The reversal of 33215430055 is 55003451233.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 33215430055 - 23 = 33215430047 is a prime.

It is a super-2 number, since 2×332154300552 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33215429999 and 33215430026.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 322854 + ... + 413116.

It is an arithmetic number, because the mean of its divisors is an integer number (4982437404).

Almost surely, 233215430055 is an apocalyptic number.

33215430055 is a deficient number, since it is larger than the sum of its proper divisors (6644069177).

33215430055 is an equidigital number, since it uses as much as digits as its factorization.

33215430055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163865.

The product of its (nonzero) digits is 27000, while the sum is 31.

Adding to 33215430055 its reverse (55003451233), we get a palindrome (88218881288).

The spelling of 33215430055 in words is "thirty-three billion, two hundred fifteen million, four hundred thirty thousand, fifty-five".

Divisors: 1 5 73597 90263 367985 451315 6643086011 33215430055