Base | Representation |
---|---|
bin | 110000001110101000000… |
… | …110101010101010100101 |
3 | 102201211122002110121002011 |
4 | 300032220012222222211 |
5 | 413300030431331000 |
6 | 11014312455314221 |
7 | 461305650036055 |
oct | 60165006525245 |
9 | 12654562417064 |
10 | 3314240105125 |
11 | 106861a1567a4 |
12 | 4563a437b971 |
13 | 1b06ba927301 |
14 | b65a5373565 |
15 | 5b3271632ba |
hex | 303a81aaaa5 |
3314240105125 has 32 divisors (see below), whose sum is σ = 4330065003264. Its totient is φ = 2527852536000.
The previous prime is 3314240105107. The next prime is 3314240105129. The reversal of 3314240105125 is 5215010424133.
It is not a de Polignac number, because 3314240105125 - 215 = 3314240072357 is a prime.
It is a super-4 number, since 4×33142401051254 (a number of 51 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3314240105129) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 994866 + ... + 2760115.
It is an arithmetic number, because the mean of its divisors is an integer number (135314531352).
Almost surely, 23314240105125 is an apocalyptic number.
It is an amenable number.
3314240105125 is a deficient number, since it is larger than the sum of its proper divisors (1015824898139).
3314240105125 is a wasteful number, since it uses less digits than its factorization.
3314240105125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3755326 (or 3755316 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 3314240105125 its reverse (5215010424133), we get a palindrome (8529250529258).
The spelling of 3314240105125 in words is "three trillion, three hundred fourteen billion, two hundred forty million, one hundred five thousand, one hundred twenty-five".
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