Base | Representation |
---|---|
bin | 110000000001100100001… |
… | …001100001111001000001 |
3 | 102200111102122221200002112 |
4 | 300001210021201321001 |
5 | 413032320031244131 |
6 | 11004033051025105 |
7 | 460301256346133 |
oct | 60014411417101 |
9 | 12614378850075 |
10 | 3300215103041 |
11 | 106268243108a |
12 | 45372b43b195 |
13 | 1ac2940a32cc |
14 | b5a3482d053 |
15 | 5aca5c4202b |
hex | 30064261e41 |
3300215103041 has 8 divisors (see below), whose sum is σ = 3585972268800. Its totient is φ = 3025664100720.
The previous prime is 3300215103007. The next prime is 3300215103047. The reversal of 3300215103041 is 1403015120033.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3300215103041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3300215102998 and 3300215103016.
It is not an unprimeable number, because it can be changed into a prime (3300215103047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2801540246 + ... + 2801541423.
It is an arithmetic number, because the mean of its divisors is an integer number (448246533600).
Almost surely, 23300215103041 is an apocalyptic number.
3300215103041 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
It is an amenable number.
3300215103041 is a deficient number, since it is larger than the sum of its proper divisors (285757165759).
3300215103041 is a wasteful number, since it uses less digits than its factorization.
3300215103041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5603081719.
The product of its (nonzero) digits is 1080, while the sum is 23.
The spelling of 3300215103041 in words is "three trillion, three hundred billion, two hundred fifteen million, one hundred three thousand, forty-one".
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