Base | Representation |
---|---|
bin | 101110111001110001001… |
… | …010011000101111111111 |
3 | 102102010110001110220021222 |
4 | 232321301022120233333 |
5 | 410301424222121343 |
6 | 10504403245343555 |
7 | 451602006064502 |
oct | 56716112305777 |
9 | 12363401426258 |
10 | 3223124020223 |
11 | 1032a12534598 |
12 | 4407b5867bbb |
13 | 1a4c29811c83 |
14 | b200014b139 |
15 | 58c92d24a68 |
hex | 2ee71298bff |
3223124020223 has 2 divisors, whose sum is σ = 3223124020224. Its totient is φ = 3223124020222.
The previous prime is 3223124020187. The next prime is 3223124020253. The reversal of 3223124020223 is 3220204213223.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3223124020223 - 28 = 3223124019967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3223124020192 and 3223124020201.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3223124020253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1611562010111 + 1611562010112.
It is an arithmetic number, because the mean of its divisors is an integer number (1611562010112).
Almost surely, 23223124020223 is an apocalyptic number.
3223124020223 is a deficient number, since it is larger than the sum of its proper divisors (1).
3223124020223 is an equidigital number, since it uses as much as digits as its factorization.
3223124020223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 3223124020223 its reverse (3220204213223), we get a palindrome (6443328233446).
The spelling of 3223124020223 in words is "three trillion, two hundred twenty-three billion, one hundred twenty-four million, twenty thousand, two hundred twenty-three".
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