Base | Representation |
---|---|
bin | 100011111101101101001010… |
… | …0111101110010000111010011 |
3 | 1112111002012012200212122121221 |
4 | 1013323122110331302013103 |
5 | 312430440023213143403 |
6 | 3040450234200225511 |
7 | 123430046505153025 |
oct | 10773322475620723 |
9 | 1474065180778557 |
10 | 316344020443603 |
11 | 91884822517a99 |
12 | 2b59171046b297 |
13 | 107691616ccc99 |
14 | 58191bcdba015 |
15 | 2688c79842dbd |
hex | 11fb694f721d3 |
316344020443603 has 2 divisors, whose sum is σ = 316344020443604. Its totient is φ = 316344020443602.
The previous prime is 316344020443597. The next prime is 316344020443609. The reversal of 316344020443603 is 306344020443613.
It is a balanced prime because it is at equal distance from previous prime (316344020443597) and next prime (316344020443609).
It is a cyclic number.
It is not a de Polignac number, because 316344020443603 - 245 = 281159648354771 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 316344020443603.
It is not a weakly prime, because it can be changed into another prime (316344020443609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158172010221801 + 158172010221802.
It is an arithmetic number, because the mean of its divisors is an integer number (158172010221802).
Almost surely, 2316344020443603 is an apocalyptic number.
316344020443603 is a deficient number, since it is larger than the sum of its proper divisors (1).
316344020443603 is an equidigital number, since it uses as much as digits as its factorization.
316344020443603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1492992, while the sum is 43.
The spelling of 316344020443603 in words is "three hundred sixteen trillion, three hundred forty-four billion, twenty million, four hundred forty-three thousand, six hundred three".
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