Base | Representation |
---|---|
bin | 100011110100111000000110… |
… | …0101100001010010001001100 |
3 | 1112022210012001002110001111110 |
4 | 1013221300030230022101030 |
5 | 312301044333124020400 |
6 | 3034120551101052020 |
7 | 123243300612050103 |
oct | 10751601454122114 |
9 | 1468705032401443 |
10 | 315130553345100 |
11 | 91457131a21529 |
12 | 2b4164b4857010 |
13 | 106ab8b703b04c |
14 | 57b658609703a |
15 | 26674076dae50 |
hex | 11e9c0cb0a44c |
315130553345100 has 144 divisors (see below), whose sum is σ = 936432384991488. Its totient is φ = 81762554453760.
The previous prime is 315130553345099. The next prime is 315130553345129. The reversal of 315130553345100 is 1543355031513.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1255539817 + ... + 1255790783.
It is an arithmetic number, because the mean of its divisors is an integer number (6503002673552).
Almost surely, 2315130553345100 is an apocalyptic number.
315130553345100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
315130553345100 is an abundant number, since it is smaller than the sum of its proper divisors (621301831646388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
315130553345100 is a wasteful number, since it uses less digits than its factorization.
315130553345100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364144 (or 364137 counting only the distinct ones).
The product of its (nonzero) digits is 202500, while the sum is 39.
The spelling of 315130553345100 in words is "three hundred fifteen trillion, one hundred thirty billion, five hundred fifty-three million, three hundred forty-five thousand, one hundred".
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