314104445440133 has 4 divisors (see below), whose sum is σ = 314119242863040. Its totient is φ = 314089648017228.

The previous prime is 314104445440099. The next prime is 314104445440193. The reversal of 314104445440133 is 331044544401413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 314104445440133 - 2⁴⁸ = 32629468729477 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314104445440193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7398679613 + ... + 7398722066.

It is an arithmetic number, because the mean of its divisors is an integer number (78529810715760).

Almost surely, 2^{314104445440133} is an apocalyptic number.

It is an amenable number.

314104445440133 is a deficient number, since it is larger than the sum of its proper divisors (14797422907).

314104445440133 is a wasteful number, since it uses less digits than its factorization.

314104445440133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14797422906.

The product of its (nonzero) digits is 552960, while the sum is 41.

Adding to 314104445440133 its reverse (331044544401413), we get a palindrome (645148989841546).

The spelling of 314104445440133 in words is "three hundred fourteen trillion, one hundred four billion, four hundred forty-five million, four hundred forty thousand, one hundred thirty-three".