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314032112177857 is a prime number
BaseRepresentation
bin100011101100111000100110…
…0011111101001001011000001
31112011220011202211121012022021
41013121301030133221023001
5312130100231204142412
63031520205530441441
7123101033326143343
oct10731611437511301
91464804684535267
10314032112177857
11910732a8584677
122b27963ab93281
131062c1411b3928
145779341a49293
152648a68a06607
hex11d9c4c7e92c1

314032112177857 has 2 divisors, whose sum is σ = 314032112177858. Its totient is φ = 314032112177856.

The previous prime is 314032112177813. The next prime is 314032112177977. The reversal of 314032112177857 is 758771211230413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 309656133508401 + 4375978669456 = 17597049^2 + 2091884^2 .

It is a cyclic number.

It is not a de Polignac number, because 314032112177857 - 219 = 314032111653569 is a prime.

It is a super-2 number, since 2×3140321121778572 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (314032112177257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157016056088928 + 157016056088929.

It is an arithmetic number, because the mean of its divisors is an integer number (157016056088929).

Almost surely, 2314032112177857 is an apocalyptic number.

It is an amenable number.

314032112177857 is a deficient number, since it is larger than the sum of its proper divisors (1).

314032112177857 is an equidigital number, since it uses as much as digits as its factorization.

314032112177857 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1975680, while the sum is 52.

The spelling of 314032112177857 in words is "three hundred fourteen trillion, thirty-two billion, one hundred twelve million, one hundred seventy-seven thousand, eight hundred fifty-seven".