Base | Representation |
---|---|
bin | 100011101000100001101010… |
… | …1011011000101101110001111 |
3 | 1112002202220122121221001222221 |
4 | 1013101003111123011232033 |
5 | 312040242004143304411 |
6 | 3030341103525520211 |
7 | 123006536520036652 |
oct | 10721032533055617 |
9 | 1462686577831887 |
10 | 313433114041231 |
11 | 90962267767938 |
12 | 2b1a152b873067 |
13 | 105b7800c967b2 |
14 | 575835a879899 |
15 | 26381abad7071 |
hex | 11d10d56c5b8f |
313433114041231 has 2 divisors, whose sum is σ = 313433114041232. Its totient is φ = 313433114041230.
The previous prime is 313433114041217. The next prime is 313433114041237. The reversal of 313433114041231 is 132140411334313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313433114041231 - 211 = 313433114039183 is a prime.
It is a super-2 number, since 2×3134331140412312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313433114041237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156716557020615 + 156716557020616.
It is an arithmetic number, because the mean of its divisors is an integer number (156716557020616).
Almost surely, 2313433114041231 is an apocalyptic number.
313433114041231 is a deficient number, since it is larger than the sum of its proper divisors (1).
313433114041231 is an equidigital number, since it uses as much as digits as its factorization.
313433114041231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 313433114041231 its reverse (132140411334313), we get a palindrome (445573525375544).
The spelling of 313433114041231 in words is "three hundred thirteen trillion, four hundred thirty-three billion, one hundred fourteen million, forty-one thousand, two hundred thirty-one".
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