Base | Representation |
---|---|
bin | 100011101000100001101010… |
… | …1011010111110011001100011 |
3 | 1112002202220122121212112211222 |
4 | 1013101003111122332121203 |
5 | 312040242004141324420 |
6 | 3030341103525125255 |
7 | 123006536516553341 |
oct | 10721032532763143 |
9 | 1462686577775758 |
10 | 313433114011235 |
11 | 90962267747349 |
12 | 2b1a152b85982b |
13 | 105b7800c85c4a |
14 | 575835a86c991 |
15 | 26381abacd225 |
hex | 11d10d56be663 |
313433114011235 has 16 divisors (see below), whose sum is σ = 385294047570432. Its totient is φ = 244630304947200.
The previous prime is 313433114011223. The next prime is 313433114011273. The reversal of 313433114011235 is 532110411334313.
It is a de Polignac number, because none of the positive numbers 2k-313433114011235 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 313433114011195 and 313433114011204.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 180338942 + ... + 182068668.
It is an arithmetic number, because the mean of its divisors is an integer number (24080877973152).
Almost surely, 2313433114011235 is an apocalyptic number.
313433114011235 is a deficient number, since it is larger than the sum of its proper divisors (71860933559197).
313433114011235 is a wasteful number, since it uses less digits than its factorization.
313433114011235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2613694.
The product of its (nonzero) digits is 38880, while the sum is 35.
Adding to 313433114011235 its reverse (532110411334313), we get a palindrome (845543525345548).
The spelling of 313433114011235 in words is "three hundred thirteen trillion, four hundred thirty-three billion, one hundred fourteen million, eleven thousand, two hundred thirty-five".
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