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312431140125 = 325313311016823
BaseRepresentation
bin1001000101111100101…
…10001101110100011101
31002212102212022101011100
410202332112031310131
520104324332441000
6355310123343313
731400222605356
oct4427626156435
91085385271140
10312431140125
11110557262925
1250674681b39
13236013b8920
141119c10cd2d
1581d8be4a00
hex48be58dd1d

312431140125 has 192 divisors, whose sum is σ = 632390234112. Its totient is φ = 147355200000.

The previous prime is 312431140121. The next prime is 312431140157. The reversal of 312431140125 is 521041134213.

312431140125 is a `hidden beast` number, since 3 + 1 + 243 + 11 + 401 + 2 + 5 = 666.

It is not a de Polignac number, because 312431140125 - 22 = 312431140121 is a prime.

It is a super-2 number, since 2×3124311401252 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312431140121) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 45787464 + ... + 45794286.

It is an arithmetic number, because the mean of its divisors is an integer number (3293699136).

Almost surely, 2312431140125 is an apocalyptic number.

It is an amenable number.

312431140125 is an abundant number, since it is smaller than the sum of its proper divisors (319959093987).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312431140125 is a wasteful number, since it uses less digits than its factorization.

312431140125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6989 (or 6976 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 312431140125 its reverse (521041134213), we get a palindrome (833472274338).

The spelling of 312431140125 in words is "three hundred twelve billion, four hundred thirty-one million, one hundred forty thousand, one hundred twenty-five".