Base | Representation |
---|---|
bin | 101101010101100100111… |
… | …010010101100110101101 |
3 | 102000211202122021002011110 |
4 | 231111210322111212231 |
5 | 402021113320212140 |
6 | 10343132234542233 |
7 | 441043043431215 |
oct | 55254472254655 |
9 | 12024678232143 |
10 | 3115544304045 |
11 | aa13275a0548 |
12 | 423991597979 |
13 | 197a43883394 |
14 | aab16587245 |
15 | 5609845d380 |
hex | 2d564e959ad |
3115544304045 has 16 divisors (see below), whose sum is σ = 4984892778240. Its totient is φ = 1661616331584.
The previous prime is 3115544304031. The next prime is 3115544304083. The reversal of 3115544304045 is 5404034455113.
It is not a de Polignac number, because 3115544304045 - 27 = 3115544303917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3115544303994 and 3115544304012.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6342796 + ... + 6816314.
It is an arithmetic number, because the mean of its divisors is an integer number (311555798640).
Almost surely, 23115544304045 is an apocalyptic number.
It is an amenable number.
3115544304045 is a deficient number, since it is larger than the sum of its proper divisors (1869348474195).
3115544304045 is a wasteful number, since it uses less digits than its factorization.
3115544304045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 912164.
The product of its (nonzero) digits is 288000, while the sum is 39.
Adding to 3115544304045 its reverse (5404034455113), we get a palindrome (8519578759158).
The spelling of 3115544304045 in words is "three trillion, one hundred fifteen billion, five hundred forty-four million, three hundred four thousand, forty-five".
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