Base | Representation |
---|---|
bin | 101101010100011010111… |
… | …011001100010011010100 |
3 | 102000201120010120000110210 |
4 | 231110122323030103110 |
5 | 402011043032422400 |
6 | 10342405133445420 |
7 | 441000221563125 |
oct | 55243273142324 |
9 | 12021503500423 |
10 | 3114303014100 |
11 | aa084a952a93 |
12 | 4236a5940870 |
13 | 1978a66631a5 |
14 | aaa3978a04c |
15 | 560244b8950 |
hex | 2d51aecc4d4 |
3114303014100 has 144 divisors (see below), whose sum is σ = 9236222968896. Its totient is φ = 809721984000.
The previous prime is 3114303014087. The next prime is 3114303014101. The reversal of 3114303014100 is 14103034113.
3114303014100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3114303014101) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 19934290 + ... + 20089910.
It is an arithmetic number, because the mean of its divisors is an integer number (64140437284).
Almost surely, 23114303014100 is an apocalyptic number.
3114303014100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3114303014100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4618111484448).
3114303014100 is an abundant number, since it is smaller than the sum of its proper divisors (6121919954796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3114303014100 is a wasteful number, since it uses less digits than its factorization.
3114303014100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157306 (or 157299 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 3114303014100 its reverse (14103034113), we get a palindrome (3128406048213).
The spelling of 3114303014100 in words is "three trillion, one hundred fourteen billion, three hundred three million, fourteen thousand, one hundred".
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