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3114114103 is a prime number
BaseRepresentation
bin1011100110011101…
…1001110000110111
322001000202101110101
42321213121300313
522334203122403
61233002134531
7140112350602
oct27147316067
98030671411
103114114103
111358922021
1272aab1447
133a822a389
1421782d339
151335d571d
hexb99d9c37

3114114103 has 2 divisors, whose sum is σ = 3114114104. Its totient is φ = 3114114102.

The previous prime is 3114114097. The next prime is 3114114127. The reversal of 3114114103 is 3014114113.

It is a weak prime.

It is an emirp because it is prime and its reverse (3014114113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3114114103 - 29 = 3114113591 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3114118103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557057051 + 1557057052.

It is an arithmetic number, because the mean of its divisors is an integer number (1557057052).

Almost surely, 23114114103 is an apocalyptic number.

3114114103 is a deficient number, since it is larger than the sum of its proper divisors (1).

3114114103 is an equidigital number, since it uses as much as digits as its factorization.

3114114103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 3114114103 is about 55804.2480730634. The cubic root of 3114114103 is about 1460.3092644098.

Adding to 3114114103 its reverse (3014114113), we get a palindrome (6128228216).

The spelling of 3114114103 in words is "three billion, one hundred fourteen million, one hundred fourteen thousand, one hundred three".