3113140240141 has 4 divisors (see below), whose sum is σ = 3171878735292. Its totient is φ = 3054401744992.

The previous prime is 3113140240129. The next prime is 3113140240153. The reversal of 3113140240141 is 1410420413113.

3113140240141 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (3113140240129) and next prime (3113140240153).

It can be written as a sum of positive squares in 2 ways, for example, as 1690964737641 + 1422175502500 = 1300371^2 + 1192550^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113140240141 - 2¹⁷ = 3113140109069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113140240181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29369247496 + ... + 29369247601.

It is an arithmetic number, because the mean of its divisors is an integer number (792969683823).

Almost surely, 2^{3113140240141} is an apocalyptic number.

It is an amenable number.

3113140240141 is a deficient number, since it is larger than the sum of its proper divisors (58738495151).

3113140240141 is an equidigital number, since it uses as much as digits as its factorization.

3113140240141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58738495150.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 3113140240141 its reverse (1410420413113), we get a palindrome (4523560653254).

The spelling of 3113140240141 in words is "three trillion, one hundred thirteen billion, one hundred forty million, two hundred forty thousand, one hundred forty-one".