Base | Representation |
---|---|
bin | 10010100011001… |
… | …101011110011000 |
3 | 210200121121202010 |
4 | 102203031132120 |
5 | 1114133020440 |
6 | 50514305520 |
7 | 10466220201 |
oct | 2243153630 |
9 | 720547663 |
10 | 311220120 |
11 | 14a748312 |
12 | 882882a0 |
13 | 4c628b23 |
14 | 2d4945a8 |
15 | 1c4c8580 |
hex | 128cd798 |
311220120 has 64 divisors (see below), whose sum is σ = 944939520. Its totient is φ = 81989504.
The previous prime is 311220073. The next prime is 311220121. The reversal of 311220120 is 21022113.
311220120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 311220096 and 311220105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311220121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5664 + ... + 25583.
It is an arithmetic number, because the mean of its divisors is an integer number (14764680).
Almost surely, 2311220120 is an apocalyptic number.
311220120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
311220120 is an abundant number, since it is smaller than the sum of its proper divisors (633719400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311220120 is a wasteful number, since it uses less digits than its factorization.
311220120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31344 (or 31340 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
The square root of 311220120 is about 17641.4319146718. The cubic root of 311220120 is about 677.6767021382.
Adding to 311220120 its reverse (21022113), we get a palindrome (332242233).
It can be divided in two parts, 3112 and 20120, that added together give a palindrome (23232).
The spelling of 311220120 in words is "three hundred eleven million, two hundred twenty thousand, one hundred twenty".
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