Search a number
-
+
31120055 = 56224011
BaseRepresentation
bin111011010110…
…1101010110111
32011120001200122
41312231222313
530431320210
63031002155
7525342011
oct166555267
964501618
1031120055
1116625a5a
12a50935b
1365a7a45
1441c11b1
152aeab55
hex1dadab7

31120055 has 4 divisors (see below), whose sum is σ = 37344072. Its totient is φ = 24896040.

The previous prime is 31120051. The next prime is 31120073. The reversal of 31120055 is 55002113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55002113 = 57839511.

It is not a de Polignac number, because 31120055 - 22 = 31120051 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31120051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3112001 + ... + 3112010.

It is an arithmetic number, because the mean of its divisors is an integer number (9336018).

Almost surely, 231120055 is an apocalyptic number.

31120055 is a deficient number, since it is larger than the sum of its proper divisors (6224017).

31120055 is an equidigital number, since it uses as much as digits as its factorization.

31120055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6224016.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 31120055 is about 5578.5352020042. The cubic root of 31120055 is about 314.5430680840.

Adding to 31120055 its reverse (55002113), we get a palindrome (86122168).

The spelling of 31120055 in words is "thirty-one million, one hundred twenty thousand, fifty-five".

Divisors: 1 5 6224011 31120055