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31004040212447 is a prime number
BaseRepresentation
bin1110000110010101100001…
…10011011010111111011111
311001202221211212111020112012
413003022300303122333133
513030432233243244242
6145535020501301435
76346653006363251
oct703126063327737
9131687755436465
1031004040212447
1199738154763a5
12358895a40487b
13143b88c768933
14792864213cd1
1538b7460aa282
hex1c32b0cdafdf

31004040212447 has 2 divisors, whose sum is σ = 31004040212448. Its totient is φ = 31004040212446.

The previous prime is 31004040212399. The next prime is 31004040212449. The reversal of 31004040212447 is 74421204040013.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31004040212447 - 210 = 31004040211423 is a prime.

It is a super-2 number, since 2×310040402124472 (a number of 28 digits) contains 22 as substring.

Together with 31004040212449, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31004040212449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15502020106223 + 15502020106224.

It is an arithmetic number, because the mean of its divisors is an integer number (15502020106224).

Almost surely, 231004040212447 is an apocalyptic number.

31004040212447 is a deficient number, since it is larger than the sum of its proper divisors (1).

31004040212447 is an equidigital number, since it uses as much as digits as its factorization.

31004040212447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21504, while the sum is 32.

The spelling of 31004040212447 in words is "thirty-one trillion, four billion, forty million, two hundred twelve thousand, four hundred forty-seven".