Base | Representation |
---|---|
bin | 1101111000100111001000… |
… | …01010100001010010111011 |
3 | 11000002212121022122212000121 |
4 | 12330103210022201102323 |
5 | 13000220432102044120 |
6 | 144534225540314111 |
7 | 6300616465445443 |
oct | 674234412412273 |
9 | 130085538585017 |
10 | 30532455503035 |
11 | 9801818174332 |
12 | 35114896a2937 |
13 | 14062765a1b95 |
14 | 777ac8ba5123 |
15 | 37e344dc25aa |
hex | 1bc4e42a14bb |
30532455503035 has 32 divisors (see below), whose sum is σ = 39413715505920. Its totient is φ = 22635183542400.
The previous prime is 30532455503029. The next prime is 30532455503189. The reversal of 30532455503035 is 53030555423503.
It is not a de Polignac number, because 30532455503035 - 27 = 30532455502907 is a prime.
It is a super-2 number, since 2×305324555030352 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 30532455502982 and 30532455503000.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7493601 + ... + 10826770.
It is an arithmetic number, because the mean of its divisors is an integer number (1231678609560).
Almost surely, 230532455503035 is an apocalyptic number.
30532455503035 is a deficient number, since it is larger than the sum of its proper divisors (8881260002885).
30532455503035 is a wasteful number, since it uses less digits than its factorization.
30532455503035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18320779.
The product of its (nonzero) digits is 2025000, while the sum is 43.
The spelling of 30532455503035 in words is "thirty trillion, five hundred thirty-two billion, four hundred fifty-five million, five hundred three thousand, thirty-five".
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