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25804397 is a prime number
BaseRepresentation
bin110001001101…
…1111001101101
31210112222222102
41202123321231
523101220042
62321024445
7432222323
oct142337155
953488872
1025804397
1113625253
128785125
135466398
1435d9d13
1523eab32
hex189be6d

25804397 has 2 divisors, whose sum is σ = 25804398. Its totient is φ = 25804396.

The previous prime is 25804391. The next prime is 25804399. The reversal of 25804397 is 79340852.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15888196 + 9916201 = 3986^2 + 3149^2 .

It is a cyclic number.

It is not a de Polignac number, because 25804397 - 214 = 25788013 is a prime.

Together with 25804399, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25804397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25804391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12902198 + 12902199.

It is an arithmetic number, because the mean of its divisors is an integer number (12902199).

Almost surely, 225804397 is an apocalyptic number.

It is an amenable number.

25804397 is a deficient number, since it is larger than the sum of its proper divisors (1).

25804397 is an equidigital number, since it uses as much as digits as its factorization.

25804397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 38.

The square root of 25804397 is about 5079.8028505051. The cubic root of 25804397 is about 295.5048217315.

The spelling of 25804397 in words is "twenty-five million, eight hundred four thousand, three hundred ninety-seven".